本站APP,内容更劲爆

www91zx2020com

类型:一分钟试看午夜 地区: 印度 年份:2020-07-08

剧情介绍

%potl(3xy,,)用来z绘制3维曲图线,不而能制绘曲图!面就把所是的有%(x,,yz)点连接在起。一而画曲面图须必su用rfmesh函和,而这数两个%数函都要需道对应知,x向量y交点叉所有点处的z值,所以得内用%=-x2000.3::200;=-y00:021:.200;%X[,Y]mesh=rig(xdy,);Z%=X.Y*/qrts(X*X+Y.*.Y)%得获值,z用mes再(h, XY ,)Z绘曲面图; ,下为代码面=-x200:.0:3200;=y-2000.1::00;2[XY],=esmghrd(ixy);,Z=X.*./Yqst(Xr*.+YX*.Y);meh(Xs,,ZY)%望希解决能你问的题! ###################################################################################atlma画b曲面两的交线赏分悬:00 1- 解时间决:200-91-4019: 7 3上半球面z^.+2y.^+x2^2=.1(z=>) 0与面x平y++=z1.的5线交怎该画出来么?- --------------------------[,Y,ZX=]shere(p50);(ZZ0<=)(Z(-<Z0);)eshm(XY,Z)%,上半画球面ohdl n;oemesh(z'.1-x-y'5[-, 1])%画1面平x[y,,z]m=esgrhid(lnisace(p1-,1));cnootrulsic(ex,,yz,xy++z-15,.XY,,Z,[ 00)%画交线]xis equalavewi13(,52) #0##################################################################################两线直相交funtcion[X,Y =p]l(Xl1Y1,X2,Y,2) 直线%交相交求点1AY1=()1Y1(-)2;1BX1=2)(X-1(1)C1=Y1(2;)X*(1)-1Y(11)X1*2)(;A=2Y(1)2-Y(2);22=B2X2)(-2X();1C2Y2=()*X2(1)2-2Y()*12(2X);D=det([1,BA;A1,B22)];=Xde([t-1 C1;BC- B2]2/)D;Ydet=([1 AC-;A12,-C])/D;2调用格式:x1=1[ ]5y1=[; 15];2x[1 5=]y;=25,1[;]x[,y=pll(x],11,y2,xy2)p;ltox1,y(1,r'';h)lod onlop(tx2y2,,'b';)pot(xly,,'o'k;)直线%与多直线相交x条i=1[2 4 3];5iy=[ 26 63 1;]lpto(i,yix;)hod lnox1[1 5];y1==4 [5]line;x1,(1)y;x=erzo(ssiz(eix));yx;=for i=15:-1x2=i([i x+1i];y)=2yi(i[i+1] );[x,]=ylplx(1y,1,x,y22);plot(,y,'rxo')nde直%与曲线线相交x-=:0.1:88;=y;xX[Y,=]eshmrgid(,x)y;R=qsrt(X^.2Y+.2^+)es;Z=psi(Rn)./R;contourZ(,3;h)ol don=ccotonru(,Z)3;x=0[360] y;[=0 004];=(y(y2)-(1y)/(x(2))x(-1)*(x)-x()1+y)1(;z=)0 [0];linex,y,z);c=('c;X=c:,()1;=cY:,2)(;r0a=s(Yb-((2)-yy1())(/x2)(-x1)()*(Xx(-1)+y)(1))<.9=;3z=0;yy=r0.zY;*xx=r0.X;*lpt(xoxr0~(=)0,y(yr0=~0)','r)%线与曲曲线交相=x:pi/400:2*pi;0x=x;'y1s=inpi*x(;)2=ycos(ipx*;)lpto(xy1,x,,y);h2oldon r0abs(=2-siynp(*x)i<)=002.;yy=0.*r1y;xx=r0*x.pl;o(xxt(0r~0=,yy(r)0~0)=',.'r)直与线面相曲交x=-8:.3:80y=x;[;XY,=m]ehgsri(dxy),;=Z.^2+Y.^X2;mse(Xh,,YZ;h)odl nox[=1-01 ]0;y=[10-3 ;]=[z033 5];inle(,x,yz);0=(rbsaY(y-1(-)y(2()y(1-)/()(x)2x(-)1*)X(x-1()))=0<45.&.)..(bs(aZ-(1)z-z(2()z(-1)/)((x)2x(-)1)*X(x-1()))<.45)0&...(abs(-Y(y)1(y(-)2-y(1))(/z2)-z(()1*)(Z-z1))()<0.45);=zz=0.r*Z;y=r0.*y;Yx=r0x.*X;pol3t(x(r0~x0=,y)y(r0=~)0,z(r0~=z0,')r*)'面平曲面与交相x=8:0.1-8:;yx;=[,X]=meshgriYdx(,);y1=Z*2neo(sizse(X));Z=X2.2^Y-^2;.emshX(,YZ,1;)old honmeh(XsY,Z,);2r0=(bsa(Z1Z2-<)=6.5;)zzr=.*Z10yy;r=0*Y.x;=r0.*Xx;lotp(x3(xr~=00,y)(y0~=0r,)z(rz0~=0)'k*'),cldcips('

详情

猜你喜欢

Copyright © 2020